q^2-540*q+20000=0

Solution for q^2-540*q+20000=0 equation:

q^2-540q+20000=0

a = 1; b = -540; c = +20000;
Δ = b2-4ac
Δ = -5402-4·1·20000
Δ = 211600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{211600}=460$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-460}{2*1}=\frac{80}{2}
=40
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+460}{2*1}=\frac{1000}{2}
=500
$